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8b^2-10b-2=-4
We move all terms to the left:
8b^2-10b-2-(-4)=0
We add all the numbers together, and all the variables
8b^2-10b+2=0
a = 8; b = -10; c = +2;
Δ = b2-4ac
Δ = -102-4·8·2
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-6}{2*8}=\frac{4}{16} =1/4 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+6}{2*8}=\frac{16}{16} =1 $
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